A spring has a spring constant of 40 N/m. What force stretches it by 0.05 m?
F = k × e.
Worked solution
- N
GCSE & IGCSE physics practice
Hooke's law says the extension of a spring is proportional to the force on it, up to the limit of proportionality: , where is the spring constant in N/m and is the extension in m. The energy stored in a stretched spring is .
15 questions · Foundation tier · Every answer is checked as you type it, with a full worked solution. Updated .
| GCSE (AQA) | Physics and Combined Science, Foundation and Higher. Recall F = ke (on AQA's list of equations to learn); Ee = ½ke² is given on the equation sheet. Investigating force and extension is a required practical. |
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| Cambridge IGCSE (0625) | Supplement (Extended): define the spring constant as force per unit extension and recall and use k = F ÷ x; use the limit of proportionality. Core: interpret load–extension graphs. |
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A spring has a spring constant of 40 N/m. What force stretches it by 0.05 m?
F = k × e.
Worked solution
A force of 6 N stretches a spring by 0.12 m. Calculate the spring constant.
k = F ÷ e.
Worked solution
A spring has a spring constant of 30 N/m. What force stretches it by 0.2 m?
F = ke.
Worked solution
A force of 12 N stretches a spring by 0.04 m. Calculate the spring constant.
k = F ÷ e.
Worked solution
A spring with N/m has a 10 N force applied. Calculate its extension.
e = F ÷ k.
Worked solution
A spring is 20 cm long. With a 3 N weight hung on it, it is 26 cm long. Calculate the spring constant in N/m.
Extension = 26 − 20 = 6 cm = 0.06 m.
Worked solution
A spring has N/m. What force gives an extension of 8 cm?
8 cm = 0.08 m.
Worked solution
A spring with N/m is stretched by 0.1 m. How much elastic potential energy does it store?
Ee = ½ke².
Worked solution
A spring with N/m has a 25 N force applied. Calculate its extension in cm.
e = F ÷ k gives metres; × 100 for cm.
Worked solution
A spring is 15 cm long. With a 4 N weight hung on it, it is 23 cm long. Calculate the spring constant in N/m.
Extension = new length − original length, in metres.
Worked solution
A spring with N/m is stretched by 0.15 m. How much elastic potential energy does it store?
Ee = ½ke².
Worked solution
A 2 kg mass hangs on a spring with N/m. Calculate the extension. ( N/kg)
The force is the mass's weight.
Worked solution
A spring obeys Hooke's law up to 4 N. When 6 N is hung on it, the extension is more than 1.5 times the 4 N extension. Why?
Hooke's law only holds up to a point.
Worked solution
A 0.5 kg mass hangs on a spring with N/m. Calculate the extension. ( N/kg)
The force is the weight of the mass, mg.
Worked solution
A spring stores 0.9 J of elastic potential energy when stretched by 0.06 m. Calculate its spring constant.
Rearrange Ee = ½ke² to k = 2Ee ÷ e².
Worked solution
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