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Probability

Find probabilities of single and combined events, use complements and work with and without replacement.

Also known as: chance, independent events, without replacement, Venn diagrams.

Key ideas

  • P(event) = favourable outcomes ÷ total equally likely outcomes.
  • P(not A) = 1 − P(A).
  • For independent events, P(A and B) = P(A) × P(B).
  • Without replacement, the second probability changes because the total has changed.

Single events

For equally likely outcomes, P(A)=favourabletotalP(A) = \frac{\text{favourable}}{\text{total}}. On a fair six-sided die, P(greater than 4)=26=13P(\text{greater than } 4) = \frac{2}{6} = \frac{1}{3}.

Probabilities are between 00 (impossible) and 11 (certain), and the probabilities of all outcomes sum to 11, so P(not A)=1−P(A)P(\text{not } A) = 1 - P(A).

Combined events

For independent events, multiply. Two fair coins: P(two tails)=12×12=14P(\text{two tails}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}, so P(at least one head)=1−14=34P(\text{at least one head}) = 1 - \frac{1}{4} = \frac{3}{4}.

"At least one" questions are usually easiest with the complement.

Without replacement and two-way data

From a bag of 44 red and 66 blue counters, picking two without replacement: P(both red)=410×39=215.P(\text{both red}) = \frac{4}{10} \times \frac{3}{9} = \frac{2}{15}. With overlapping groups (a Venn diagram), avoid double counting: ∣A∪B∣=∣A∣+∣B∣−∣A∩B∣|A \cup B| = |A| + |B| - |A \cap B|.

Worked examples

Example 1 · Without replacement

A bag contains 4 red and 6 blue counters. Two are taken at random without replacement. Find P(both red).

  1. Step 1.First red: 410\frac{4}{10}.
  2. Step 2.Second red (one red removed): 39\frac{3}{9}.
  3. Step 3.Multiply: 1290=215\frac{12}{90} = \frac{2}{15}.

Answer: 215\frac{2}{15}

Example 2 · Overlapping groups

Of 200 students, 120 study Spanish, 70 study French and 30 study both. One student is chosen at random. Find P(neither).

  1. Step 1.At least one language: 120+70−30=160120 + 70 - 30 = 160.
  2. Step 2.Neither: 200−160=40200 - 160 = 40.
  3. Step 3.P=40200=0.2P = \frac{40}{200} = 0.2.

Answer: 0.2

Common mistakes

  • Adding probabilities that should be multiplied (and vice versa).
  • Keeping the same denominator after an item is removed.
  • Counting the overlap twice in Venn diagram problems.

Try it yourself

Original practice questions. Your answer is checked instantly.

Question 1ProbabilityEasier

A fair six-sided die is rolled. What is the probability of rolling a number greater than 4?

Question 2ProbabilityEasier

A bag contains 3 red, 5 blue and 2 green marbles. One marble is chosen at random. What is the probability that it is blue?

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