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Vectors in maths: column vectors, magnitude and proofs

TutorAura guide · Updated

A vector has both size (magnitude) and direction, unlike a scalar, which only has size. In maths, vectors describe movements: "3 right and 4 up". They're written as column vectors, bold letters such as a\mathbf{a}, or with arrows such as AB→\overrightarrow{AB}. GCSE and IGCSE questions range from simple arithmetic to geometric proofs.

Key takeaways

  • A column vector shows the move across (top) and up or down (bottom).
  • Add and subtract vectors one component at a time.
  • Magnitude uses Pythagoras: the length of (3, 4) is 5.
  • Parallel vectors are multiples of each other.

Column vectors

(3−2)\begin{pmatrix} 3 \\ -2 \end{pmatrix}

means 3 to the right and 2 down. The top number is the horizontal move (positive right, negative left); the bottom is the vertical move (positive up, negative down). It's the same notation used for translations in transformations.

Adding, subtracting and multiplying by a number

Let a=(2−1)\mathbf{a} = \begin{pmatrix} 2 \\ -1 \end{pmatrix} and b=(−34)\mathbf{b} = \begin{pmatrix} -3 \\ 4 \end{pmatrix}.

  • a+b=(−13)\mathbf{a} + \mathbf{b} = \begin{pmatrix} -1 \\ 3 \end{pmatrix} (add the tops, add the bottoms).
  • 2a=(4−2)2\mathbf{a} = \begin{pmatrix} 4 \\ -2 \end{pmatrix} (multiply both numbers).
  • 2a−b=(4−(−3)−2−4)=(7−6)2\mathbf{a} - \mathbf{b} = \begin{pmatrix} 4 - (-3) \\ -2 - 4 \end{pmatrix} = \begin{pmatrix} 7 \\ -6 \end{pmatrix}.

−a-\mathbf{a} is the same length as a\mathbf{a} but points the opposite way.

Magnitude

The magnitude (length) of a vector comes from Pythagoras:

∣(xy)∣=x2+y2\left| \begin{pmatrix} x \\ y \end{pmatrix} \right| = \sqrt{x^2 + y^2}

The magnitude of (34)\begin{pmatrix} 3 \\ 4 \end{pmatrix} is 9+16=5\sqrt{9 + 16} = 5. Check it with our Pythagoras calculator.

Vectors between points

If A is at (1,2)(1, 2) and B is at (5,−1)(5, -1), then

AB→=(5−1−1−2)=(4−3)\overrightarrow{AB} = \begin{pmatrix} 5 - 1 \\ -1 - 2 \end{pmatrix} = \begin{pmatrix} 4 \\ -3 \end{pmatrix}

and ∣AB→∣=5|\overrightarrow{AB}| = 5, the same answer as the distance between two points. With position vectors OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}: AB→=b−a\overrightarrow{AB} = \mathbf{b} - \mathbf{a} ("end minus start").

Vector journeys in geometry

To find a vector in a diagram, find a route along vectors you know. Going against an arrow means subtracting.

Example: OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}. M is the midpoint of AB.

OM→=OA→+12AB→=a+12(b−a)=12a+12b\overrightarrow{OM} = \overrightarrow{OA} + \tfrac{1}{2}\overrightarrow{AB} = \mathbf{a} + \tfrac{1}{2}(\mathbf{b} - \mathbf{a}) = \tfrac{1}{2}\mathbf{a} + \tfrac{1}{2}\mathbf{b}

If instead P divides AB in the ratio 1:21 : 2, then AP→=13AB→\overrightarrow{AP} = \tfrac{1}{3}\overrightarrow{AB}, so OP→=a+13(b−a)=23a+13b\overrightarrow{OP} = \mathbf{a} + \tfrac{1}{3}(\mathbf{b} - \mathbf{a}) = \tfrac{2}{3}\mathbf{a} + \tfrac{1}{3}\mathbf{b}. A ratio of 1:21 : 2 means thirds, not halves.

Parallel and collinear

  • Two vectors are parallel if one is a multiple of the other: (6−4)=2(3−2)\begin{pmatrix} 6 \\ -4 \end{pmatrix} = 2\begin{pmatrix} 3 \\ -2 \end{pmatrix}, so they're parallel.
  • Three points are collinear (on one straight line) if, say, AB→\overrightarrow{AB} and BC→\overrightarrow{BC} are parallel and share the point B.

In a proof, write the conclusion in words: "AC→=3AB→\overrightarrow{AC} = 3\overrightarrow{AB}, so AC is parallel to AB, and they share point A, so A, B and C are collinear."

Common mistakes

  • Swapping the top and bottom numbers.
  • Getting AB→\overrightarrow{AB} the wrong way round: it's b−a\mathbf{b} - \mathbf{a}, not a−b\mathbf{a} - \mathbf{b}.
  • Forgetting to simplify: collect the a\mathbf{a} terms and the b\mathbf{b} terms.
  • Leaving out the words in a proof.

Practice questions

  1. p=(15)\mathbf{p} = \begin{pmatrix} 1 \\ 5 \end{pmatrix}, q=(4−2)\mathbf{q} = \begin{pmatrix} 4 \\ -2 \end{pmatrix}. Find 3p+q3\mathbf{p} + \mathbf{q}.
  2. Find the magnitude of (−68)\begin{pmatrix} -6 \\ 8 \end{pmatrix}.
  3. Are (25)\begin{pmatrix} 2 \\ 5 \end{pmatrix} and (−4−10)\begin{pmatrix} -4 \\ -10 \end{pmatrix} parallel?

Answers: 1. (713)\begin{pmatrix} 7 \\ 13 \end{pmatrix}. 2. 36+64=10\sqrt{36 + 64} = 10. 3. Yes: the second is −2-2 times the first (parallel, opposite direction).

More practice in our vectors questions.

Frequently asked questions

What is a vector in maths?

A vector is a quantity with size and direction, such as a movement of 3 right and 4 up. It's often written as a column vector.

How do you find the magnitude of a vector?

Use Pythagoras: square each component, add them and take the square root. The magnitude of (3, 4) is 5.

How do you show two vectors are parallel?

Show that one is a multiple of the other, for example (6, 9) = 3 × (2, 3).

Sources

  1. GCSE mathematics: subject content and assessment objectives. Department for Education.
  2. Cambridge IGCSE Mathematics 0580 syllabus. Cambridge International.