A car accelerates from rest to 10 m/s over 25 m. Calculate its acceleration.
u = 0, v = 10, s = 25.
Worked solution
- , so
GCSE & IGCSE physics practice
At GCSE, the "SUVAT" equation you need is , linking initial speed , final speed , acceleration and distance for uniform acceleration. It's on the equation sheet. Use it when there's no time in the question. Deceleration means is negative.
8 questions · Foundation tier · Every answer is checked as you type it, with a full worked solution. Updated .
| GCSE (AQA) | Physics and Combined Science, Foundation and Higher: (final velocity)² − (initial velocity)² = 2 × acceleration × distance, given on the equation sheet. |
|---|---|
| Cambridge IGCSE (0625) | Not in the 2026 to 2028 syllabus: Cambridge uses a = Δv ÷ Δt and speed–time graphs instead. |
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A car accelerates from rest to 10 m/s over 25 m. Calculate its acceleration.
u = 0, v = 10, s = 25.
Worked solution
A cyclist starts from rest and accelerates at 2 m/s² for 16 m. What is the final speed?
v² = u² + 2as.
Worked solution
A car travelling at 20 m/s brakes with a deceleration of 4 m/s² until it stops. Calculate the braking distance.
v = 0 and a = −4.
Worked solution
A stone is dropped from a height of 20 m. Calculate its speed when it hits the ground, to 3 significant figures. ( m/s², ignore air resistance)
u = 0, a = 9.8, s = 20.
Worked solution
A car speeds up from 5 m/s to 15 m/s with an acceleration of 2 m/s². How far does it travel while speeding up?
s = (v² − u²) ÷ 2a.
Worked solution
A ball is thrown straight up at 14 m/s. How high does it go? (Deceleration 9.8 m/s², ignore air resistance)
At the top, v = 0.
Worked solution
A plane must reach 80 m/s to take off and can accelerate at 4 m/s² from rest. What is the shortest runway it needs?
u = 0, v = 80, a = 4.
Worked solution
A car stops in 32 m with a deceleration of 4 m/s². How fast was it going when the brakes were applied?
v = 0, so u² = 2 × 4 × 32.
Worked solution
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