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Arc length and sector area calculator

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A sector is a slice of a circle between two radii. Enter the radius and the angle at the centre (in degrees), and the calculator finds the arc length, the area of the sector and its perimeter. Each is a fraction of the whole circle:

arc length=θ360×2πrsector area=θ360×πr2\text{arc length} = \frac{\theta}{360} \times 2\pi r \qquad \text{sector area} = \frac{\theta}{360} \times \pi r^2
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Worked example

Radius 6 cm, angle 60°. The sector is 60÷360=1660 \div 360 = \tfrac{1}{6} of the circle.

  • Arc length =16×2π×6=2π≈6.28= \tfrac{1}{6} \times 2\pi \times 6 = 2\pi \approx 6.28 cm.
  • Sector area =16×π×36=6π≈18.85= \tfrac{1}{6} \times \pi \times 36 = 6\pi \approx 18.85 cm².
  • Perimeter =2π+6+6≈18.28= 2\pi + 6 + 6 \approx 18.28 cm.

Perimeter of a sector

The perimeter is the arc plus the two straight radii. Forgetting the radii is the most common mistake in these questions: the arc alone is just the curved edge.

Working backwards

  • Finding the angle from an arc length: θ=arc2πr×360\theta = \dfrac{\text{arc}}{2\pi r} \times 360. An arc of 5 cm on a circle of radius 10 cm gives θ=5÷62.83×360≈28.6°\theta = 5 \div 62.83 \times 360 \approx 28.6°.
  • Finding the radius from the sector area: r=area×360θπr = \sqrt{\dfrac{\text{area} \times 360}{\theta \pi}}.

Rearranging these is a common Higher-tier exam question.

Segments

A segment is the region between a chord and the arc. Its area is the sector area minus the area of the triangle formed by the two radii and the chord: 12r2sin⁡θ\tfrac{1}{2} r^2 \sin\theta. For radius 6 and 60°, the triangle is 12×36×sin⁡60°≈15.59\tfrac{1}{2} \times 36 \times \sin 60° \approx 15.59, so the segment is 18.85−15.59≈3.2618.85 - 15.59 \approx 3.26 cm².

Common mistakes

  • Using 180 instead of 360 in the fraction.
  • Using the diameter as the radius.
  • Leaving the two radii out of the perimeter.

Practise with our arc length and sector area questions, and use the circle calculator for whole circles.

Exam tips

  • Write the fraction θ360\tfrac{\theta}{360} first: it shows the method even if a later step slips.
  • Exact answers keep π\pi: 2π2\pi cm, 6π6\pi cm².
  • Radians appear at A level; at GCSE and IGCSE, angles are in degrees.

Sectors in real life

  • Pie charts: each slice is a sector. A category that's 25% of the data gets 0.25×360=90°0.25 \times 360 = 90°, and its share of the pie's area is also 25%.
  • Clock hands: the minute hand of a clock sweeps 6° each minute. In 20 minutes it turns 120°, so the tip of a 10 cm hand travels an arc of 120360×2π×10≈20.9\tfrac{120}{360} \times 2\pi \times 10 \approx 20.9 cm.
  • Windscreen wipers and sprinklers cover sectors (or the region between two arcs), which is why these shapes appear so often in exam questions.

When a question gives the arc length or area and asks for the angle or radius, rearrange the same formulas: the calculator's working shows the fraction θ360\tfrac{\theta}{360} you need.

Frequently asked questions

How do you find the arc length?

Arc length = θ/360 × 2πr, where θ is the angle at the centre in degrees.

How do you find the area of a sector?

Sector area = θ/360 × πr².

What is the perimeter of a sector?

The arc length plus two radii.

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No. The calculation runs in your browser and nothing is stored.

Sources

  1. GCSE mathematics: subject content and assessment objectives. Department for Education.
  2. Cambridge IGCSE Mathematics 0580 syllabus. Cambridge International.